最近好多分享这个问题的代码，题目说的是用面向对象或者函数式编程，下面是PYTHON的实现示例

复制代码 代码如下:
#!/usr/bin/python
#encoding:utf8

'''
The Game of "FizzBuzzWhizz"
author : wang.jiankui89@gmail.com
mobile : 130-2199-5152
'''
import sys

class teacher:
    def __init__(self, student_num):
        self.student_num = student_num

    def gameStart(self, numList):
        for i in range (1, self.student_num + 1):
            stu = student(i)
            print stu.answer(numList)

class student:
    def __init__(self, my_num):
        self.my_num = my_num

    def judgeMod(self, numList):
        modRes = ""
        for num in numList:
            if self.my_num % num == 0:
                modRes += rule[num]
        return modRes if modRes else self.my_num

    def judgeContain(self, first_num):
        conRes = ""
        if str(first_num) in str(self.my_num) :
            conRes = rule[first_num]
        return conRes

    def answer(self, numList):
        conRes = self.judgeContain(numList[0])
        return conRes if conRes else self.judgeMod(numList)

def getOps():
    '''parse options'''
    if len(sys.argv) != 4 :
        print "use as fizzBuzzWhizz.py [0-9] [0-9] [0-9]"
        sys.exit()
    else:
        first_num = int(sys.argv[1])
        second_num = int(sys.argv[2])
        third_num = int(sys.argv[3])
    return first_num, second_num, third_num

def main():
    first_num, second_num, third_num = getOps()
    global rule
    rule = {first_num:"Fizz", second_num:"Buzz", third_num:"Whizz"}

    student_num = 100

    tea = teacher(100)
    tea.gameStart( (first_num, second_num, third_num) )

if __name__ == "__main__":
    main()